Asked by Kid
Verify/prove that:
(cotA+cotB)/(tanA+tanB)+(1-cotAcotB)/(1-tanAtanB) = 0
(cotA+cotB)/(tanA+tanB)+(1-cotAcotB)/(1-tanAtanB) = 0
Answers
Answered by
Steve
tan(A+B) = (tanA+tanB)/(1-tanAtanB)
that should get you started.
that should get you started.
Answered by
Kid
I'm sorry, I just still don't understand exactly how you even got tan(A+B) = (tanA+tanB)/(1-tanAtanB). What happened to the cotA+cotB, 1-cotAcotB, and 0? If you simplified the original identity, then how did you do that? Because what I did was expand the cot and tan into sin and cos, but then I get stuck and I am unable to match (cotA+cotB)/(tanA+tanB)+(1-cotAcotB)/(1-tanAtanB) to 0.
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