Asked by ZK
tarzan swings a vine of length 4m in a vertical circle under the influence of gravity. When the vine makes an angle of 20degrees with the vertical, Tarzan has a speed of 5m/s. Find centripetal acceleration, tangential acceleration and the resultant acceleration.
Explain the answer properly.
Explain the answer properly.
Answers
Answered by
Anonymous
Height of Tarzan above hanging straight down = 4(1-cos 20)= .241 meters
v = 5
Ac = v^2/R = 25/4 = 6.25 m/s^2
which is radial acceleration
weight = m g = 9.81 m
tangential component of weight
= m g sin 20 = 3.36 m
so
tangential acceleration = 3.36 m/s^2
toward equilibrium point
resultant a = sqrt (3.36^2 + 6.25^2)
v = 5
Ac = v^2/R = 25/4 = 6.25 m/s^2
which is radial acceleration
weight = m g = 9.81 m
tangential component of weight
= m g sin 20 = 3.36 m
so
tangential acceleration = 3.36 m/s^2
toward equilibrium point
resultant a = sqrt (3.36^2 + 6.25^2)
Answered by
Anonymous
tarzan swings from a vine whose length is 10m in a vertical circle under the influence of gravity .when vine make an angle of 20 degree with the vertical then find out length of arc and centripetal force experienced at this instant when tarzan has a speed of 10m/s and weighs 980N
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