Asked by kelvin
The distance between two towns P and Q is 390 km. John left town P at 7:30 am and travelled towards town Q at an average speed of 60 km/hr. Half an hour later Patrick left town Q and travelled towards town P at the same speed. At what time did they meet?
* please guys assist me this question**
* please guys assist me this question**
Answers
Answered by
sara
velocity=distance/time
to find the time patrick reached
to find the time patrick reached
Answered by
sara
sorry john
Answered by
sara
its more physics than math, anyways, i guess but im not sure
since patrick left after 30 min,
u need to add 30 min on johns arrival time.
since patrick left after 30 min,
u need to add 30 min on johns arrival time.
Answered by
Scott
when Patrick left (at 8:00 am), John had traveled 30 km
... so the distance between them was 360 km
they are closing the distance at 120 kph
how long 'til they meet?
what time is it?
... so the distance between them was 360 km
they are closing the distance at 120 kph
how long 'til they meet?
what time is it?
Answered by
sara
i used to take that material last year ,now i forgot it, sorry
Answered by
Reiny
time taken by John --- t hours
time taken by Pt = t - 1/2
distance covered by John = 60t km
distance covered by Pat = 60(t-1/2) = 60t - 30
60t + 60t - 30 = 390
120t =420
t = 3.5 hrs
finish it up
time taken by Pt = t - 1/2
distance covered by John = 60t km
distance covered by Pat = 60(t-1/2) = 60t - 30
60t + 60t - 30 = 390
120t =420
t = 3.5 hrs
finish it up
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