approach speed = 60 + 40 = 100 km/hr
so crash in 4 hours
60*4 = 240 km from T1
so crash in 4 hours
60*4 = 240 km from T1
Car A is traveling towards Car B, so their speeds will add up to determine their combined relative speed. In this case, the relative speed of Car A with respect to Car B is (60 km/h + 40 km/h) = 100 km/h.
Now, since the two cars are traveling in opposite directions, you can consider their distance as the sum of their distances from their respective starting points. The total distance between the two towns is given as 400 km, so you can express the equation as:
Distance traveled by Car A + Distance traveled by Car B = Total distance between the towns
Let's assume that the meeting point is 'x' km from T1 (where Car A starts). Therefore, the distance traveled by Car A would be 'x' km. Similarly, the distance traveled by Car B would be (400 - x) km (as Car B starts from T2).
Now, you can substitute the distances and solve the equation:
x + (400 - x) = 400
Simplifying the equation:
x + 400 - x = 400
400 = 400
Since this equation is true, it means that any value of 'x' can satisfy the equation, as long as it falls between 0 and 400. Therefore, the meeting point can be anywhere along the route between the two towns.
In summary, the point where the two cars will meet can vary along the route between T1 and T2, as long as it falls within the 400 km distance between the towns.