Asked by akash
a right circular cylindrical container ,contains 2160cubic cm water. if the diameter of the base of the cylindrical container is 24 cm, then find the height of the cylindrical container.
Answers
Answered by
Bosnian
V = A ∙ h
V = Volume of a circular cylinder
A = Area of a base
h = height
In this case:
A = d²∙ π / 4
so:
V = A ∙ h
V = ( d²∙π / 4 ) ∙ h
V = 2160 cm³
d = 24 cm
2160 = ( 24²∙ π / 4 ) ∙ h
2160 = ( 576 ∙ π / 4 ) ∙ h
2160 = 576 π ∙ h / 4
Multiply both sides by 4
2160 ∙ 4 = 576 π ∙ h
8640 = 576 π ∙ h
Divide both sides by 576 π
8640 / ( 576 π ) = h
576 ∙ 15 / ( 576 π ) = h
15 / π = h
h = 15 / π
h = 15 / 3.141592654
h = 4.774648292 cm
h = 15 / π cm
h ≈ 4.775 cm
V = Volume of a circular cylinder
A = Area of a base
h = height
In this case:
A = d²∙ π / 4
so:
V = A ∙ h
V = ( d²∙π / 4 ) ∙ h
V = 2160 cm³
d = 24 cm
2160 = ( 24²∙ π / 4 ) ∙ h
2160 = ( 576 ∙ π / 4 ) ∙ h
2160 = 576 π ∙ h / 4
Multiply both sides by 4
2160 ∙ 4 = 576 π ∙ h
8640 = 576 π ∙ h
Divide both sides by 576 π
8640 / ( 576 π ) = h
576 ∙ 15 / ( 576 π ) = h
15 / π = h
h = 15 / π
h = 15 / 3.141592654
h = 4.774648292 cm
h = 15 / π cm
h ≈ 4.775 cm
Answered by
Saroj
Thanks to solve my problem
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