Asked by dinesh
a. A closed cylindrical can is to hold 1000cm^3 of liquid. How should we choose the height and radius of this can to minimize the amount of material need to manufacture the can?
b.a manufacturer wants to design a open box having a square base and surface of 108cm^2. What dimensions will produce a box with minimum volume?
b.a manufacturer wants to design a open box having a square base and surface of 108cm^2. What dimensions will produce a box with minimum volume?
Answers
Answered by
Steve
πr^2 h = 1000, so h = 1000/(πr^2)
surface area is
a = 2πr^2 + 2πrh
= 2πr^2 + 2000/r
da/dr = 4πr - 2000/r^2
= 4(πr^3 - 500)/r^2
da/dr=0 when r = ∛(500/π)
thus, h = 100/∛(250π)
Do the other along the same way.
surface area is
a = 2πr^2 + 2πrh
= 2πr^2 + 2000/r
da/dr = 4πr - 2000/r^2
= 4(πr^3 - 500)/r^2
da/dr=0 when r = ∛(500/π)
thus, h = 100/∛(250π)
Do the other along the same way.
Answered by
dinesh
steve bro...
hw bout the b?
plz tell me...
hw bout the b?
plz tell me...
Answered by
Rick
dinesh bro...
the b is the same as the a
the b is the same as the a
Answered by
dejen
h=234.43
Answered by
abebe
answer
Answered by
abebe
-1+x^2
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