Asked by Anonymous
solve (v+6)^2 -40=0, where v is a real number.
Answers
Answered by
Steve
(v+6)^2-40 = 0
(v+6)^2 = 40
v+6 = ±√40
v = -6±√40
or,
v = -6±2√10
(v+6)^2 = 40
v+6 = ±√40
v = -6±√40
or,
v = -6±2√10
Answered by
Bosnian
( v + 6 )² - 40 = 0
Add 40 to both sides
( v + 6 )² - 40 + 40 = 0 + 40
( v + 6 )² = 40
v + 6 = ± √ 40
v + 6 = ± √4 ∙ √10
v + 6 = ± 2 √10
Subtract 6 to both sides
v + 6 - 6 = ± 2 √10 - 6 =
± 2 ( √10 - 3 )
The solutions are:
v₁ = - 2 √10 - 6 = - 2 ( √10 + 3 )
v₂ = 2 √10 - 6 = 2 ( √10 - 3 )
Add 40 to both sides
( v + 6 )² - 40 + 40 = 0 + 40
( v + 6 )² = 40
v + 6 = ± √ 40
v + 6 = ± √4 ∙ √10
v + 6 = ± 2 √10
Subtract 6 to both sides
v + 6 - 6 = ± 2 √10 - 6 =
± 2 ( √10 - 3 )
The solutions are:
v₁ = - 2 √10 - 6 = - 2 ( √10 + 3 )
v₂ = 2 √10 - 6 = 2 ( √10 - 3 )
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