Asked by sam
a hydrauli press has a ram of 30 cm diameter and plunger of 4.5cm diameter. find the the weight lifted by the hydraulic press when the force applied at the plunger is 500N
Answers
Answered by
Scott
the force is proportional to the square of the diameter
w = (30 / 4.5)^2 * 500 N
w = (30 / 4.5)^2 * 500 N
Answered by
haile
i want answer
Answered by
Anonymous
F/a=w/A
W=FA/a
W=500*(30^2)/(4.5^2)
W=22222.22N
W=22.22KN
W=FA/a
W=500*(30^2)/(4.5^2)
W=22222.22N
W=22.22KN
Answered by
Tariku
the answer of the questions
Answered by
Maria
7. A hydraulic press has a ram of 35 cm diameter and a plunger of 5 cm diameter. It is used for lifting a weight of 30KN. Find the force required at the plunger in kN.
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