Asked by Thousif
Three particles of equal masses travelling with velocities of 10m/s,20m/s and 30m/s respectively along x-axis at an angle of 30° to the direction of positive x-axis and Y-axis collide simultaneously and get sticked to each other
1)The combined particle will move with velocity
Ans:10/3√20+2√3m/s
Combined particle will move at angle α wth X-axis where
Ans: α=taninverse [2(√3+2)]
1)The combined particle will move with velocity
Ans:10/3√20+2√3m/s
Combined particle will move at angle α wth X-axis where
Ans: α=taninverse [2(√3+2)]
Answers
Answered by
Henry
1. M*V1 + M*V2 + M*V3 = M*V + M*V + M*V.
M*10[30o] + M*20[30] + M*30[30] = 3MV.
Divide both sides by M:
10[30o] + 20[30] + 30[30] = 3V,
60[30o] = 3V,
V = 20m/s[30o].
M*10[30o] + M*20[30] + M*30[30] = 3MV.
Divide both sides by M:
10[30o] + 20[30] + 30[30] = 3V,
60[30o] = 3V,
V = 20m/s[30o].
Answered by
Suma
Pls send the solution how like that answers will get in the above question
Answered by
Narra
10/3(√20+2√3)
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