Asked by Mike

A club with 25 members wishes to select a 4-member leadership team. How many ways can this be done?
25x4=100
100 variations in the leadership team
Would this be correct by any chance?
Answered by bobpursley
if the team does not have specific idenity, such as secretary, VP, Pres, etc, ie they are all the same..

25C4= 25!/(4!*21!)= 25*24*23*22/(4*3*2)
=12,650
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