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If sin theta is 8÷17;cos beta is 9÷41 where theta is obtuse and beta is acute. Find sin(theta + beta)
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Answered by
Steve
We have angle a in QII, and angle b in QI. So,
sin a = 8/17
cos a = -15/17
sin b = 40/41
cos b = 9/41
sin(a+b) = sin a * cos b + cos a * sin b
= (8/17)(9/41)+(-15/17)(40/41) = -528/697
sin a = 8/17
cos a = -15/17
sin b = 40/41
cos b = 9/41
sin(a+b) = sin a * cos b + cos a * sin b
= (8/17)(9/41)+(-15/17)(40/41) = -528/697
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