Asked by Lena
I did this experiment where I filled a graduated cylinder with water. The I put a stopper on it and put it under water and removed the stopper. The with a modified lighter (that wouldn't release sparks) I added butane gas. I got the following results:
mass of lighter = 15.15 g
final mass of lighter = 15.00 g
volume of butane = 80.0 mL
temperature = 25.0 degrees celsius
atmosperic pressure = 101.4 Kpa
How would I find the water vapour pressure?
mass of lighter = 15.15 g
final mass of lighter = 15.00 g
volume of butane = 80.0 mL
temperature = 25.0 degrees celsius
atmosperic pressure = 101.4 Kpa
How would I find the water vapour pressure?
Answers
Answered by
Lena
Thank you.
Answered by
bobpursley
see above.
There are no AI answers yet. The ability to request AI answers is coming soon!