Question

In the experiment 0.500 g of copper reacted with oxygen to give 0.563 g of copper oxide. What is the empirical formula of the oxide expressed as a chemical formula?
..........Cu + O2 ==> CuxOy
I.....0.500g...0.......0
C..............x.........
E.....0.500+x..-x.....0.563

Therefore, g Cu = 0.500
grams oxygen = 0.0.063

mols Cu = 0.500/atomic mass Cu = ?
mols O = 0.063/16 = ?

Now find the ratio of the mols to each other with the smaller number being 1.00.
Post your work if you get stuck.

Sn2O3

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