Question

. Determine the temperature, T that results when 150 g of ice at 0°C is mixed with 300 g of water at 50°C. Given heat of fusion, l of water = 3.35 × 105 J/kg, cwater = 4186 J/kg∙oC.

Answer 1

Sum of heats gained is zero (some gains, some loses).

Heat ice + heat water=0
150*Hfice+150*cw*(Tf-0)+300*cw*(Tf-50)=0
solve for Tfinal, Tf