16. From the standard enthalpies of formation, calculate the Horxn for the reaction: (Hof = -151.9 kJ/mol for C6H12.)
C6H12(l) + 9 O2(g) 6 CO2 (g) + 6 H2O(l)
1 answer
dHrxn = (n*dHf products) - (n*dHf reactants)
C6H12(l) + 9 O2(g) 6 CO2 (g) + 6 H2O(l)
1 answer