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16. From the standard enthalpies of formation, calculate the Horxn for the reaction: (Hof = -151.9 kJ/mol for C6H12.)

C6H12(l) + 9 O2(g)  6 CO2 (g) + 6 H2O(l)

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dHrxn = (n*dHf products) - (n*dHf reactants)

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