Haven't you seen this before?
dHrxn = (n*dHf products) - (n*dHf reactants)
Post your work if you get stuck.
16. From the standard enthalpies of formation, calculate the ƒ´Horxn for the reaction: (ƒ´Hof = -151.9 kJ/mol for C6H12.)
C6H12(l) + 9 O2(g) „³ 6 CO2 (g) + 6 H2O(l)
1 answer
1 answer