Asked by Josh
                How do we integrate ln| 1 - cot x |  0-pi/4?
            
            
        Answers
                    Answered by
            Josh
            
    1-cotx=1-(cosx/sinx)= 1 - ((1/2)(cot(x/2))) - ((1/2)(sec(x/2))) 
how to simplify this inside "ln"?
can we substract them adding ln(loge) infront of them?
    
how to simplify this inside "ln"?
can we substract them adding ln(loge) infront of them?
                    Answered by
            Steve
            
    I think you're stuck. There's just no way to get things to just a product.
According to wolframalpha, the integral is not elementary.
http://www.wolframalpha.com/input/?i=integral+log(1-cotx)+dx
    
According to wolframalpha, the integral is not elementary.
http://www.wolframalpha.com/input/?i=integral+log(1-cotx)+dx
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