Asked by Josh
How do we integrate ln| 1 - cot x | 0-pi/4?
Answers
Answered by
Josh
1-cotx=1-(cosx/sinx)= 1 - ((1/2)(cot(x/2))) - ((1/2)(sec(x/2)))
how to simplify this inside "ln"?
can we substract them adding ln(loge) infront of them?
how to simplify this inside "ln"?
can we substract them adding ln(loge) infront of them?
Answered by
Steve
I think you're stuck. There's just no way to get things to just a product.
According to wolframalpha, the integral is not elementary.
http://www.wolframalpha.com/input/?i=integral+log(1-cotx)+dx
According to wolframalpha, the integral is not elementary.
http://www.wolframalpha.com/input/?i=integral+log(1-cotx)+dx
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