Asked by gigi
how much 0.1F HC2H3O2 is required to make 500 ml of solution with a Ph of 4.0?
Answers
Answered by
DrBob222
HC2H3O2 = HAc
Let Y = (HAc) needed to make pH = 4.0 or (H^+) of 1E-4 M.
.......HAc ==> H^+ + Ac^-
I......Y.......0.....0
C.....-x.......x.....x
E.....Y-x......x.....x
Ka = (H^+)(Ac^-)/(HAc)
Ka = (x)(x)/(Y-x)
You know Ka (or you can look it up), you know x, solve for Y. I will use Y as the answer but you substitute that into the following.
mL1 x M1 = mL2 x M2
500 x Y = mL2 x 0.1
Solve for mL2. That will be the volume in mL of the 0.1M HAc needed.
Let Y = (HAc) needed to make pH = 4.0 or (H^+) of 1E-4 M.
.......HAc ==> H^+ + Ac^-
I......Y.......0.....0
C.....-x.......x.....x
E.....Y-x......x.....x
Ka = (H^+)(Ac^-)/(HAc)
Ka = (x)(x)/(Y-x)
You know Ka (or you can look it up), you know x, solve for Y. I will use Y as the answer but you substitute that into the following.
mL1 x M1 = mL2 x M2
500 x Y = mL2 x 0.1
Solve for mL2. That will be the volume in mL of the 0.1M HAc needed.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.