Asked by manish

If A + B + C = π, prove that: ( sin2A + sin2B + sin2C ) / ( sinA + sinB + sinC ) = 8 sin(A/2) sin(B/2) sin(C/2)
Answered by Steve
The sum-to-product formulas will make this just drop out easily.
Answered by Anish kumar
Sin2A+SIN2B+SIN2C/SIN A+SIN B +SIN C =8 SIN A/2+SIN B/2 +SIN C/2


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