Asked by ruchiket

two particles moving along x-axis in the same direction with uniform velocity is 8 metre per second and 4 metre per second initially the first particle is 21 m to the left of the origin and the second one is 7 m to the right of the origin to particle meets from the origin at a distance of
Answered by Damon
particle 1
x = -21 + 8 t
particle 2
x = 7 + 4 t
so
-21 + 8 t = 7 + 4 t

4 t = 28
t = 4 seconds
x = 7 + 16 = 23

Answered by Tony
1 st particle
x+21=u¹t
21+x=8t
x=-21+8t....
2 nd particle
x-7=u²t
x=7+4t
equating 1st and 2 nd particles
-21+8t=7+4t
8t-4t=21-7
4t=28
t=28/4 = 7 sec
SUBSTITUTION
x=-21+8t
x=-21+8(7)
x= -21+56=35
(or)
x=7+4t
x=7+4(7)
x=7+28=35
Answered by Anonymous
Correct 😀😀
Answered by Liliyana
nice solution very easy understanding thanks
Answered by Anonymous
Very nice answer bro
Answered by Anonymous
Why u took x plus 21=u1t
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