Question

How do I solve 4|8x-2|=8?
And also 6w-1 over 5 -3w= 12w-16 over 15?

Answer 1

4 | 8 x - 2 | = 8

Divide both sides by 4

| 8 x - 2 | = 2

± ( 8 x - 2 ) = 2


1.

8 x - 2 = 2

Add 2 to both sides

8 x - 2 + 2 = 2 + 2

8 x = 4

Divide both sides by 8

x = 4 / 8 = 1 / 2


2.

- ( 8 x - 2 ) = 2

- 8 x + 2 = 2

Subtract 2 to both sides

- 8 x + 2 - 2 = 2 - 2

- 8 x = 0

x = 0


4 | 8 x - 2 | = 8

The solutions are:

x = 0 and x = 1 / 2


If 6w-1 over 5 -3w= 12w-16 over 15 mean:

6 w - 1 / 5 - 3 w = 12 w - 16 / 15

then:

3 w - 1 / 5 = 12 w - 16 / 15

Subtract 3 w to both sides

3 w - 1 / 5 - 3 w = 12 w - 16 / 15 - 3 w

- 1 / 5 = 9 w -16 / 15

Add 16 / 15 to both sides

- 1 / 5 + 16 / 15 = 9 w -16 / 15 + 16 / 15

- 1 / 5 + 16 / 15 = 9 w

- 3 / 15 + 16 / 15 = 9 w

13 / 15 = 9 w

Dividey both sides by 9

( 13 / 15 ) / 9 = w

13 / 15 * 9 = w

13 / 135 = w

w = 13 / 135