Asked by Ed
How can I graph this equation: (x-squared + y-squared - 1)cubed = x-squared times y-cubed ?
Is there a polar form of the equation?
Is there a polar form of the equation?
Answers
Answered by
PsyDAG
Cannot graph here. However, here is an easier way to write your equation online. Online "^" is used to indicate an exponent, e.g., x^2 = x squared.
(x^2 + y^2 -1)^3 = x^2 * y^3
(x^2 + y^2 -1)^3 = x^2 * y^3
Answered by
Steve
first step: use real math notation
(x^2+y^2-1)^3 = x^2 y^3
As with any function, just start plugging in values for x (or y) and solving to get the other coordinate. Not easy, in this case, since high powers are difficult to solve except in special cases.
The other, easier, way is to use one of the many online graphing utilities. I like this one:
http://www.wolframalpha.com/input/?i=(x%5E2%2By%5E2-1)%5E3+%3D+x%5E2+y%5E3
As for the polar form, the graph indicates there ought to be one, but it will be messy.
(x^2+y^2-1)^3 = x^2 y^3
(r^2-1)^3 = r^5 cos^2θ sin^3θ
(r^2-1)^3 = r^5 (sin^3θ - sin^5θ)
or
8cosθ (r^2-1)^3 = sin^3(2θ)
wow. The symmetries an periodic nature of the second form make an interesting graph.
http://www.wolframalpha.com/input/?i=(r%5E2-1)%5E3+%3D+r%5E5+(sin%5E3%CE%B8+-+sin%5E5%CE%B8)
http://www.wolframalpha.com/input/?i=8cos%CE%B8+(r%5E2-1)%5E3+%3D+sin%5E3(2%CE%B8)
(x^2+y^2-1)^3 = x^2 y^3
As with any function, just start plugging in values for x (or y) and solving to get the other coordinate. Not easy, in this case, since high powers are difficult to solve except in special cases.
The other, easier, way is to use one of the many online graphing utilities. I like this one:
http://www.wolframalpha.com/input/?i=(x%5E2%2By%5E2-1)%5E3+%3D+x%5E2+y%5E3
As for the polar form, the graph indicates there ought to be one, but it will be messy.
(x^2+y^2-1)^3 = x^2 y^3
(r^2-1)^3 = r^5 cos^2θ sin^3θ
(r^2-1)^3 = r^5 (sin^3θ - sin^5θ)
or
8cosθ (r^2-1)^3 = sin^3(2θ)
wow. The symmetries an periodic nature of the second form make an interesting graph.
http://www.wolframalpha.com/input/?i=(r%5E2-1)%5E3+%3D+r%5E5+(sin%5E3%CE%B8+-+sin%5E5%CE%B8)
http://www.wolframalpha.com/input/?i=8cos%CE%B8+(r%5E2-1)%5E3+%3D+sin%5E3(2%CE%B8)
Answered by
Ed
Thx Steve. Are there any handheld graphic calculators (eg TI-84 Plus CE) that can graph this?
Answered by
Steve
don't know. some probably can do polar coordinates, but the implicit definition makes it tricky. They wouldn't look as nice as the online ones, that's for sure.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.