Asked by Sherhaida malali
7) A population of ants is growing at a rate of 8% a year. If there are 160 ants in the initial population, find
the number of ants after 6 years.
the number of ants after 6 years.
Answers
Answered by
Bosnian
8% + 100% = 108% = 108 / 100 = 1.08
The n-th term of a geometric sequence with initial value a1 and common ratio r is given by:
an = a1 ∙ r ⁿ⁻¹
In tis case :
a1 = 160
r = 1.08
Need to notice that term two is after one year, so term 7 will be after 6 years.
n = 7
so:
a6 = a1 ∙ r⁷⁻¹
a6 = 160 ∙ r⁶
a6 = 160 ∙ 1.08⁶
a6 = 160 ∙ 1.586874322944
a6 = 253.89989167104
The number of ants after 6 years will be 253.
The n-th term of a geometric sequence with initial value a1 and common ratio r is given by:
an = a1 ∙ r ⁿ⁻¹
In tis case :
a1 = 160
r = 1.08
Need to notice that term two is after one year, so term 7 will be after 6 years.
n = 7
so:
a6 = a1 ∙ r⁷⁻¹
a6 = 160 ∙ r⁶
a6 = 160 ∙ 1.08⁶
a6 = 160 ∙ 1.586874322944
a6 = 253.89989167104
The number of ants after 6 years will be 253.
Answered by
Anonymous
Why plusing this 100 % and rate of 8%
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