Asked by Dhruv
Q.Give answer without adding :-
(i) (1+3+5+7+9+11+13+15+17+19+21+23)
(i) (1+3+5+7+9+11+13+15+17+19+21+23)
Answers
Answered by
Steve
well, you probably know that the sum of the 1st n odd numbers is n^2 ...
if not, just work in from the ends. You have 6 pairs of numbers that each add to 24. (1+23, 3+21, ...)
if not, just work in from the ends. You have 6 pairs of numbers that each add to 24. (1+23, 3+21, ...)
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