Asked by rose
find the slant asymptote of t(x)=2x^2-4x+5/3-x
Answers
Answered by
Steve
Just divide:
(2x^2-4x+5)/(3-x) = -2x-2 + 11/(3-x)
As x gets huge, the 11/(3-x) becomes negligible, and the asymptote is thus
y = -2x-2
(2x^2-4x+5)/(3-x) = -2x-2 + 11/(3-x)
As x gets huge, the 11/(3-x) becomes negligible, and the asymptote is thus
y = -2x-2
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