Asked by Yashi
Generator is supplying power to a factory by cables of resistance 20 ohm if the generator is generating 50 kilowatt power at 5000 volt.what is the power receiver factory?
Answers
Answered by
Damon
Power = i V
50,000 = i (5000)
i = 10 amps
Power lost = i^2 R = 100(20) = 2000 watts
so
Power received at factory = 50,000 - 2,000
= 48 kilowtts
50,000 = i (5000)
i = 10 amps
Power lost = i^2 R = 100(20) = 2000 watts
so
Power received at factory = 50,000 - 2,000
= 48 kilowtts
Answered by
krish
50,000kese aaya
Answered by
Shreya
It is given in the question.
Answered by
Sayandeep Dey
Given,
Resistance(R)=20 ohm
Volts supplied(V)=5000V
Power(P)=50kW=50,000W
We know,
P=Vi
Or, i=50,000/5000
Or, i=10 A
Power lost= i^2R
=10×10×20
=2000 W
Power recieved at the factory=(50,000-2000)W
=48000 W = 58 kW.
I think it will help.👍👍
Resistance(R)=20 ohm
Volts supplied(V)=5000V
Power(P)=50kW=50,000W
We know,
P=Vi
Or, i=50,000/5000
Or, i=10 A
Power lost= i^2R
=10×10×20
=2000 W
Power recieved at the factory=(50,000-2000)W
=48000 W = 58 kW.
I think it will help.👍👍
Answered by
Sayandeep Dey
Sorry. It will be 48 kW
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.