Asked by Anonymous

A 60.0-Hz ac generator with a peak voltage of 110 V drives a series RC circuit with R = 10.0  and C = 10.0 mF. The impedance is
Answered by oobleck
Recall that
Z^2 = R^2 + 1/(ωC)^2
and ω = 2πf
Answered by henry2,
Xc = 1/(2pi*F*C) = 1/(377*10^-5) = 265.3 ohms.
Z = 10 - j265.3 = 265.5 ohms.[-88o].
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