Asked by Kayla
Devon speeds past Tamara in his space shuttle. In Tamara's frame of reference, the shuttle moves with a speed of 0.88c. Devon's radio is blaring out music with a beat that occurs every 0.50 seconds. How often does Tamara hear the beats?
I'm getting 0.24 s but it's saying that's wrong...
0.50=t./(the root of: 1-(0.88c^2/c^2))
0.50=t./0.474974
t.=0.2375
Thanks for your time :)
I'm getting 0.24 s but it's saying that's wrong...
0.50=t./(the root of: 1-(0.88c^2/c^2))
0.50=t./0.474974
t.=0.2375
Thanks for your time :)
Answers
Answered by
Scott
remember the twins paradox?
one stays on Earth, the other goes on a high speed (close to c) trip
the one on Earth grows old, but when the traveler returns, he is still young
time passes slower in the high speed reference frame
so the beats will be wider spaced for Tamara
one stays on Earth, the other goes on a high speed (close to c) trip
the one on Earth grows old, but when the traveler returns, he is still young
time passes slower in the high speed reference frame
so the beats will be wider spaced for Tamara
Answered by
Scott
moving time = fixed time * dilation factor
0.50 = t * 0.474974
not sure why you had division, not multiplication
0.50 = t * 0.474974
not sure why you had division, not multiplication
Answered by
Kayla
You're right that does make sense, I got confused & mixed up t & t. if I switch them I get 1.1s.
Thank you :) I appreciate your help
Thank you :) I appreciate your help
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