Asked by Joe

Suppose that the weather forecast calls for a 30% chance of rain on each of the three days of a long weekend. What are the odds in favour of no rain throughout the entire long weekend?

Claudia and Ally are the two favourites to win an upcoming golf tournament. If Claudia is given 1:9 odds of winning, and Ally is given 2:17 odds of winning,
a) who is favoured to win? Explain.
b) determine the probability of each player winning.
Answered by PsyDAG
Rain = (1-.3)^3

Claudia = 1/9 = .11

Ally = 2/17 = .12

I'll let you explain.
Answered by Reiny
the concept of odds is not quite the same as probability
odds in favour of some event = prob(the event) : prob(not the event)

prob(rain for 3 days) = .3^3 = 27/1000 = .027
prob(no rain on any of the 3 days) = 1-.027 = .973 or 973/1000

so odds in favour of no rain at all = 973/1000 : 27/1000
= 973 : 27
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