Asked by alisha
If F (x)= 2x^2-5x-3
Determine f (-4)
F (-4)=2 (-4)^2-5 (-4)-3
(I'm confused like do I use bedmas to solve this? )
F (-4)= 16-(-20)-3
F (-4)=36-3
F (-4)=33
Is that right?
Determine f (-4)
F (-4)=2 (-4)^2-5 (-4)-3
(I'm confused like do I use bedmas to solve this? )
F (-4)= 16-(-20)-3
F (-4)=36-3
F (-4)=33
Is that right?
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