almost. You forgot the 2x^2
f(-4) = 2*16+20-3
If F (x)= 2x^2-5x-3
Determine f (-4)
F (-4)=2 (-4)^2-5 (-4)-3
(I'm confused like do I use bedmas to solve this? )
F (-4)= 16-(-20)-3
F (-4)=36-3
F (-4)=33
Is that right?
4 answers
Ohh. So the answer is f (-4)=49
that's better.
Thank you
1 answer