Solve. (-10x^3+30x-20) / (-5x+5)

A) 2x^2-2x+4
B) -2x^2-2x-4
C) -2x^2+2x+4
D) 2x^2+2x-4***

Simplfy x/6x-x^2
A) 1/6-x; where x=0,6 *****
B) 1/6-x ; where x= 6
C) 1/6x ; where x = 0
D) 1/6

Simplfy x-2/x^2+4x-12
A) 1/x+6; where x=-6
B) 1/x+6; where x= -6,2***
C) 1/x+2; where x=-2
D) x+2

Simplfy x^2+3x-4/x+4
A) 1/x-4; where x=4
B) x-4
C) x-1; where x=1
D) x-1; where x= -4***

Multiply x-5/4x+8*(12x^2+32x+16)
A)(3x+2)/4(x-5)
B)(x-5)(3x+2)/4
C)(x-5)(3x+2)*****
D)(x-5)(12x+8)

I have my answers, but it would be nice if someone can break it down step by step.

4 answers

http://calc101.com/webMathematica/long-divide.jsp#topdoit
many can be done faster by factoring though
eg

Solve. (-10x^3+30x-20) / (-5x+5)
A) 2x^2-2x+4
B) -2x^2-2x-4
C) -2x^2+2x+4
D) 2x^2+2x-4***
===========================================
(2x^3-6x+4)/(x-1)

(2x^2+2x-4) (x-1)/(x-1)
so I agree

By the way, where you type "where" do you not mean "not where"? In other words NOT where the denominator = 0 ?
3 and 4 won't come up on the link
To check answers, it would be necessary to post the questions correctly, i.e. use the correct symbols, e.g. type not= or ≠ (done by & ne; but skip the space between & and ;)
Also, use parentheses appropriately, as in the first question.
x/6x-x^2 means (x/6x) - (x²)
while
x/(6x-x^2) means (x)/(6x-x²) which is probably what you mean.
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