Asked by Matthew
A 86.3mL sample of water is initially at 17.4 degC. How many kilojoules (kJ) of heat must be added to raise the temperature of the water to 31.8? The specific heat capacity of water is 4.184 J/g.degC.
How do I set this up to find the answer. Really confused,we haven't been taught this.
How do I set this up to find the answer. Really confused,we haven't been taught this.
Answers
Answered by
bobpursley
heat=masswater*c*deltatemp
= 86.3g*4.184J/gC*(31.8-17.4)
of course, this assumes you know the density of water to be 1g/ml
= 86.3g*4.184J/gC*(31.8-17.4)
of course, this assumes you know the density of water to be 1g/ml
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