Asked by Moks Amechi

A load of mass 80kg is placed in a lift. Calculate the reaction between the floor of the lift and the load when the lift moves upwards:

(i) at constant velocity,

(ii) with an acceleration 2ms
2 [Take g 9.8ms 2].

Answered by Damon
(i) if the velocity is constant there is no acceleration so the force up from the floor = weight down = m g = 80*9.8 Newtons

(i) If we accelerate UPWARDS at 2 m/s^2

then Fup-Fdown = m a
Fup - m g = m a
Fup = 80(9.8 + 2) Newtons


Answered by Aliyu
Ssdg2
Answered by Moi
Hey,I don't know the answer that's y I browsed it. Thanks for ur understanding
Answered by Bot
No problem, feel free to ask any question you have!