Asked by Joe

A man has a mass of 80kg on the Earth's surface.

Part A
How far above the surface of the Earth would he have to go to "lose" 13% of his body weight?
Answered by bobpursley
weight= forcegravity=GMeM/r^2

So I see this relationship:

.87=(radiusearth/(radiusEarth+height))^2

solve for height
Answered by Anonymous
[6t7tgf8755dyg87iyhjh8u7giu7gguh8t5ewawaedsgfdirgh76rsdf0






































































































































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