Asked by Joe
A man has a mass of 80kg on the Earth's surface.
Part A
How far above the surface of the Earth would he have to go to "lose" 13% of his body weight?
Part A
How far above the surface of the Earth would he have to go to "lose" 13% of his body weight?
Answers
Answered by
bobpursley
weight= forcegravity=GMeM/r^2
So I see this relationship:
.87=(radiusearth/(radiusEarth+height))^2
solve for height
So I see this relationship:
.87=(radiusearth/(radiusEarth+height))^2
solve for height
Answered by
Anonymous
[6t7tgf8755dyg87iyhjh8u7giu7gguh8t5ewawaedsgfdirgh76rsdf0
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