Asked by Its me
Find the perimeter and area.
a.
(1,4), (4,5), (5,2)
b.
(0,–2), (0,2), (4,0)
c.
(0, 0), (2, 0), (4,–3)
a.
(1,4), (4,5), (5,2)
b.
(0,–2), (0,2), (4,0)
c.
(0, 0), (2, 0), (4,–3)
Answers
Answered by
Steve
for the perimeters, just find the lengths of the sides and add them up.
The areas are a bit trickier, but
(a) once you get the sides, you will see that it is a right triangle, so the area is easy.
(b) is easy, since it is easy to see that it is isosceles, with base=4 and height=4
(c) is a little tougher, but you can use Heron's formula, giving the area as
√(((7+√13)/2)((3+√13)/2)((-3+√13)/2)((7-√13)/2)) = 3
note that the line from (0,0) to (4,-3) is 3x+4y=0. The altitude is the distance from (2,0) to that line, which is 6/5, making the area = 3, or
note that the perpendicular to 3x+4y=0 through (2,0) is y = 4/3 (x-2). The two lines intersect at (32/25,-24/25), so the altitude is 6/5, making the area = 3
The areas are a bit trickier, but
(a) once you get the sides, you will see that it is a right triangle, so the area is easy.
(b) is easy, since it is easy to see that it is isosceles, with base=4 and height=4
(c) is a little tougher, but you can use Heron's formula, giving the area as
√(((7+√13)/2)((3+√13)/2)((-3+√13)/2)((7-√13)/2)) = 3
note that the line from (0,0) to (4,-3) is 3x+4y=0. The altitude is the distance from (2,0) to that line, which is 6/5, making the area = 3, or
note that the perpendicular to 3x+4y=0 through (2,0) is y = 4/3 (x-2). The two lines intersect at (32/25,-24/25), so the altitude is 6/5, making the area = 3
Answered by
Reiny
What tools do you have?
Do you know how to find the distance between two points?
Do you know how to find angles of a triangle knowing the sides?
Do you know how to find the distance between two points?
Do you know how to find angles of a triangle knowing the sides?
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