Asked by mary
find the perimeter and area of a right triangle if the shortest side is 9 inches and the longest side is 41 inches
Answers
Answered by
Ms. Sue
a^2 + b^2 = c^2
9^2 + b^2 = 41^2
81 + b^2 = 1,681
b^2 = 1,600
b = 40
The perimeter is the sum of the three sides.
Area = 1/2 base times height
9^2 + b^2 = 41^2
81 + b^2 = 1,681
b^2 = 1,600
b = 40
The perimeter is the sum of the three sides.
Area = 1/2 base times height
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