Asked by Ryan
A toddler applies a 25.0 N force to a chair over a distance of 2.5 m, the chair is being pushed across a smooth floor against a force of friction (10.0 N resistance). How much work is being done?
Answers
Answered by
MathMate
Work due to frictional resistance
= frictional force * Distance
Here
force = 10.0 N (due to friction)
Distance = 2.5 m
= frictional force * Distance
Here
force = 10.0 N (due to friction)
Distance = 2.5 m
Answered by
Ryan
The answer says 62 J not 25
Answered by
MathMate
From the data given, I cannot explain the difference. If you have a diagram, please post.
Perhaps someone else can enlighten you on this.
Perhaps someone else can enlighten you on this.
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