Question
A body of mass 300g is whirled in a horizontal circle by means of a 60cm long cord. If the cord can sustain a tension of 400N before, find the max. number of revolution per minute which the body can have
Answers
Damon
m omega^2 R = 400
0.300 w^2 (0.60) = 400
solve for w ( omega ) in radians/sec
then
w * 1 rev/2pi rad * 60 sec/min
= RPM
0.300 w^2 (0.60) = 400
solve for w ( omega ) in radians/sec
then
w * 1 rev/2pi rad * 60 sec/min
= RPM