Asked by Anonymous
The base of a solid is a region located in quadrant 1 that is bounded by the axes, the graph of y = x^2 - 1, and the line x = 2. If cross-sections perpendicular to the x-axis are squares, what would be the volume of this solid?
Answers
Answered by
Steve
Hmmm. The y-axis does not form part of the boundary.
Each square of thickness dx has a base that is y=x^2-1 in width.
So, adding up all the squares, the volume v is
∫[1,2] (x^2-1)^2 dx = 38/15
Each square of thickness dx has a base that is y=x^2-1 in width.
So, adding up all the squares, the volume v is
∫[1,2] (x^2-1)^2 dx = 38/15
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