Question

How to prepare 50ml 0.04N H2SO4 from solution 0.025N sulfuric acid by adding 0.4N sulfuric acid
let x = mL of 0.4
and 50-x = mL of 0.025
---------------------
0.025(50-x) + 0.4x = 50(.04)
solve for x and 50-x

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