Asked by Gabriella
                Sulfuric acid (H2SO4)is prepared commercially from elemental sulfur using the contactprocess. In a typical sequence of reactions,the sulfur is first burned:S + O2→SO2,then it is converted to SO3 using a catalyst:2SO2+O2→2SO3.The resulting SO3 is reacted with water to produce the desired product:SO3+ H2O→H2SO4. How much sulfuric acid could be prepared
from 53 moles of sulfur?
Answer in units of g
            
        from 53 moles of sulfur?
Answer in units of g
Answers
                    Answered by
            DrBob222
            
    S + O2→SO2
2SO2+O2→2SO3
SO3+ H2O→H2SO4
1 mol S = 1 mol SO2
2 mol SO2 = 2 mol SO3
1 mol SO3 = 1 mol H2SO4
Therefore, 2 mols S = 2 mol H2SO4 or
1 mol S = 1 mol H2SO4
Thus 53 mols S will produce 53 mol H2SO4. Convert mols to g. g = mols x molar mass.
    
2SO2+O2→2SO3
SO3+ H2O→H2SO4
1 mol S = 1 mol SO2
2 mol SO2 = 2 mol SO3
1 mol SO3 = 1 mol H2SO4
Therefore, 2 mols S = 2 mol H2SO4 or
1 mol S = 1 mol H2SO4
Thus 53 mols S will produce 53 mol H2SO4. Convert mols to g. g = mols x molar mass.
                    Answered by
            Gabriella
            
    thank you
    
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