The table shows the drink preferences of 50 shoppers at the mall. What is the probability that one shopper, selected at random from the 50 surveyed, preferred either Drink B or Drink A?

Didn't you read the two responses to your last post????

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My answer is 3/10 because if you add up the amount of a and be you get 15. 15/50 = 3/10 :)

mine is different it is five slots in the chart and it is drink e or drink c

drinks - number of ppl who preferred

A- 10
B-15
C-7
D-3
E-6
hope that makes sense

it is 7/25

3/10

WHICH ONEEEEE

WHICH ONEE

it 3/10 cause 15 divided by 5 is 3 and 50 divided by 5 is 10. so you get 3/10

illl risk it

sup

hello jiskha i promise it wont happen again.

The table shows the drink preferences of 50 shoppers at the mall. What is the probability that one shopper, selected at random from the 50 surveyed, preferred either Drink B or Drink A?

A two column table is shown titled 'Drink Survey.' The first column is titled 'Drink' and contains upper A, upper B, upper C, upper D, and upper E from top to bottom. The second column is titled 'Number of Shoppers' and contains 7, 8, 10, 11, and 14 from top to bottom.
A. start fraction 8 over 25 end fraction
B. start fraction 3 over 10 end fraction
C. start fraction 11 over 25 end fraction
D. Start Fraction 7 over 25 End Fraction

The total number of shoppers surveyed is 50. The number of shoppers who preferred Drink A or Drink B is 10 + 15 = 25.

Therefore, the probability that one shopper, selected at random from the 50 surveyed, preferred either Drink B or Drink A is:

25/50 = 1/2

This is equivalent to:

2/2 * 1/2 = 1/2

So the correct answer is not listed.

Hi

Hello! How can I assist you today?

The table shows the drink preferences of 50 shoppers at the mall. What is the probability that on shopper, selected at random from the 50 surveyed , preferred either Drink B or Drink A

Drink. Number of Shoppers
A. 7
B. 8
C. 10
D. 11
E 14

Answers: 8/25, 3/10, 11/25, 7/25

The number of shoppers who preferred Drink A or Drink B can be found by adding their individual counts: 7 (for Drink A) and 8 (for Drink B) which is 7 + 8 = 15.

Therefore, the probability that one shopper, selected at random from the 50 surveyed, preferred either Drink A or Drink B is:

15/50 = 3/10

Hence, the correct answer is option B, 3/10.

Ok thank you

You're welcome!

On Friday nights the local diner severs three main entrees, each with a choice of vegetable. The entrees are beef., chicken and fish The vegetables are spinach, broccoli, and carrots. How many possible dinners entree and vegetable combinations does the diner serve? List them

There are three main entrees (beef, chicken, and fish) and for each entree, there are three choices of vegetable (spinach, broccoli, and carrots).

To find the total number of possible dinner entree and vegetable combinations, we can use the multiplication (or product) principle of counting, which states that if there are "m" ways to do one thing and "n" ways to do another, then there are m x n ways to do both things.

Using this principle, we can multiply the number of entrees by the number of vegetable choices for each entree:

3 (entrees) x 3 (vegetable choices per entree) = 9

So, there are 9 possible dinner entree and vegetable combinations. Here they are listed:

- Beef with spinach
- Beef with broccoli
- Beef with carrots
- Chicken with spinach
- Chicken with broccoli
- Chicken with carrots
- Fish with spinach
- Fish with broccoli
- Fish with carrots