The table shows the drink preferences of 50 shoppers at the mall. What is the probability that one shopper, selected at random from the 50 surveyed, preferred either Drink B or Drink A?
8/25
3/10
11/25
7/25***
7 years ago
7 years ago
YOU CANNOT COPY AND PASTE TO THIS SITE!
7 years ago
My answer is 3/10 because if you add up the amount of a and be you get 15. 15/50 = 3/10 :)
5 years ago
mine is different it is five slots in the chart and it is drink e or drink c
5 years ago
drinks - number of ppl who preferred
A- 10
B-15
C-7
D-3
E-6
hope that makes sense
4 years ago
it is 7/25
3 years ago
3/10
3 years ago
WHICH ONEEEEE
3 years ago
WHICH ONEE
3 years ago
it 3/10 cause 15 divided by 5 is 3 and 50 divided by 5 is 10. so you get 3/10
2 years ago
illl risk it
2 years ago
sup
2 years ago
hello jiskha i promise it wont happen again.
1 year ago
The table shows the drink preferences of 50 shoppers at the mall. What is the probability that one shopper, selected at random from the 50 surveyed, preferred either Drink B or Drink A?
A two column table is shown titled 'Drink Survey.' The first column is titled 'Drink' and contains upper A, upper B, upper C, upper D, and upper E from top to bottom. The second column is titled 'Number of Shoppers' and contains 7, 8, 10, 11, and 14 from top to bottom.
A. start fraction 8 over 25 end fraction
B. start fraction 3 over 10 end fraction
C. start fraction 11 over 25 end fraction
D. Start Fraction 7 over 25 End Fraction
1 year ago
The total number of shoppers surveyed is 50. The number of shoppers who preferred Drink A or Drink B is 10 + 15 = 25.
Therefore, the probability that one shopper, selected at random from the 50 surveyed, preferred either Drink B or Drink A is:
25/50 = 1/2
This is equivalent to:
2/2 * 1/2 = 1/2
So the correct answer is not listed.
1 year ago
Hi
1 year ago
Hello! How can I assist you today?
1 year ago
The table shows the drink preferences of 50 shoppers at the mall. What is the probability that on shopper, selected at random from the 50 surveyed , preferred either Drink B or Drink A
Drink. Number of Shoppers
A. 7
B. 8
C. 10
D. 11
E 14
Answers: 8/25, 3/10, 11/25, 7/25
1 year ago
The number of shoppers who preferred Drink A or Drink B can be found by adding their individual counts: 7 (for Drink A) and 8 (for Drink B) which is 7 + 8 = 15.
Therefore, the probability that one shopper, selected at random from the 50 surveyed, preferred either Drink A or Drink B is:
15/50 = 3/10
Hence, the correct answer is option B, 3/10.
1 year ago
Ok thank you
1 year ago
You're welcome!
1 year ago
On Friday nights the local diner severs three main entrees, each with a choice of vegetable. The entrees are beef., chicken and fish The vegetables are spinach, broccoli, and carrots. How many possible dinners entree and vegetable combinations does the diner serve? List them
1 year ago
There are three main entrees (beef, chicken, and fish) and for each entree, there are three choices of vegetable (spinach, broccoli, and carrots).
To find the total number of possible dinner entree and vegetable combinations, we can use the multiplication (or product) principle of counting, which states that if there are "m" ways to do one thing and "n" ways to do another, then there are m x n ways to do both things.
Using this principle, we can multiply the number of entrees by the number of vegetable choices for each entree:
3 (entrees) x 3 (vegetable choices per entree) = 9
So, there are 9 possible dinner entree and vegetable combinations. Here they are listed:
- Beef with spinach
- Beef with broccoli
- Beef with carrots
- Chicken with spinach
- Chicken with broccoli
- Chicken with carrots
- Fish with spinach
- Fish with broccoli
- Fish with carrots