Question

7.f(x)=2x^2-3x+1

13. f(x)=x^2-6x+1=0

*Solve for the zeros/roots of the following quadratic equations by using the quadratic formula*

Any help please.....
2x^2-3x+1 = (2x-1)(x-1)

x^2-6x+1 is a little harder, as it has no rational roots. So, use the quadratic formula to get

x = 3±2√2

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