Asked by Casey
Factor quadratic expressions:
2x^2 + 9x + 4
10x^2 + 70x + 100
Solve quadratic equations by factoring:
2x^2 + 9x + 4 = 0
Solve by taking square roots:
(x - 5)^2 - 81 = 0
2x^2 + 9x + 4
10x^2 + 70x + 100
Solve quadratic equations by factoring:
2x^2 + 9x + 4 = 0
Solve by taking square roots:
(x - 5)^2 - 81 = 0
Answers
Answered by
bobpursley
2x^2 + 9x + 4 = 0
(2x+1)(x+4)=0
x=-1/2, -4
(x - 5)^2 - 81 = 0
x-5=+- 9
x=14, -4
(2x+1)(x+4)=0
x=-1/2, -4
(x - 5)^2 - 81 = 0
x-5=+- 9
x=14, -4
Answered by
Reiny
2nd:
10x^2 + 70x + 100
= 10(x^2 + 7x + 10)
= 10(x+5)(x+2)
3rd:
2x^2 + 9x + 4 = 0
(2x + 1)(x + 4) = 0
carry on
4th:
real easy ...
(x-5)^2 - 81 = 0
(x-5)^2 = 81
take √ of both sides
x-5= ±9
x = 5 ± 9
= 14 or -4
10x^2 + 70x + 100
= 10(x^2 + 7x + 10)
= 10(x+5)(x+2)
3rd:
2x^2 + 9x + 4 = 0
(2x + 1)(x + 4) = 0
carry on
4th:
real easy ...
(x-5)^2 - 81 = 0
(x-5)^2 = 81
take √ of both sides
x-5= ±9
x = 5 ± 9
= 14 or -4
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