Question

The product of numbers
3^(1/3).3^(1/9).3^(1/27)...... To infinity is
A.3
B.3^(1/3)
C.3^(1/2)
D.3√3

Answer 1

I am titally lost in this question and have absolutely no idea. Is there some rule or particular formula of solving such questions?

Answer 2

the exponents form a converging geometric series

multiplying (product) numbers with the same base (3 in this case) means adding the exponents

3^(1/3 + 1/9 + 1/27 + ...)

there is a formula for the sum of an infinite geometric series
... look it up

Answer 3

and the told riddle of moving to the door, 1/2 way, the 1/4 way, then 1/8 way...does she ever reach the door?