Asked by Xx
Two coins were tossed 10 times. The result is shown in the table below.
Toss: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.
Result: 1)HH, 2)TT, 3)HT, 4)TH, 5)HT, 6)HH, 7) TH, 8)TT, 9) TH, 10) HT
What is the experimental probability that at least one of the coins landed on heads? Express the probability as a decimal.
A 0.8
B: 0.2*
C: 0.6
Toss: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10.
Result: 1)HH, 2)TT, 3)HT, 4)TH, 5)HT, 6)HH, 7) TH, 8)TT, 9) TH, 10) HT
What is the experimental probability that at least one of the coins landed on heads? Express the probability as a decimal.
A 0.8
B: 0.2*
C: 0.6
Answers
Answered by
Steve
you have it exactly backwards.
0.2 is the probability that NO heads showed.
0.2 is the probability that NO heads showed.
Answered by
MathMate
Experimental probability means you go with the number of success in the experiment divided by the total number of trials.
Here success is defined as at least one of the coins landed on heads, i.e. includes HH, HT, TH.
Count the total number of the above outcomes and divide by 10 to get the experimental probability.
Hint: the only outcome excluded is TT. Here it is easier to count the number of failures (TT) and subtract from 10 to get the number of successes.
Here success is defined as at least one of the coins landed on heads, i.e. includes HH, HT, TH.
Count the total number of the above outcomes and divide by 10 to get the experimental probability.
Hint: the only outcome excluded is TT. Here it is easier to count the number of failures (TT) and subtract from 10 to get the number of successes.
Answered by
Xx
Oh my god I must be very dumb, I am so lost.
So am I supposed to add up the toss which gives me 55 and divide by 10?
So am I supposed to add up the toss which gives me 55 and divide by 10?
Answered by
Steve
No. There were 10 tosses. 8 of them showed at least one H
So, P = 8/10 = 0.8
So, P = 8/10 = 0.8
Answered by
Help! pls
Ohhh! I get it, I over thought it. Thank you so much for everyone who helped!
Answered by
Help! pls
The answer the this specific question was 0.75.
Answered by
MathMate
Don't know you're under xx or "help! pls", but this question cannot have an answer of 0.75 because it deals with <i>experimental</i> probability, which bases it on the outcomes of the experiment.
However, the theoretical probability, which is the mathematical answer, is 0.75.
However, the theoretical probability, which is the mathematical answer, is 0.75.
Answered by
hamburblur
Two coins were tossed 10 times. The results are shown in the table.%0D%0A%0D%0A%0D%0AToss %091%092 %093 %094 %095 %096 %097 %098 %099 %0910 %0D%0AResult%09HH%09TT %09HT %09TH %09HT %09HH %09TH %09TT %09TH %09HT%0D%0A%0D%0AUse the table and information to answer the question.%0D%0A%0D%0A%0D%0A%0D%0A3. What is the experimental probability that at least one of the coins landed on heads? Express the probability as a decimal.
Answered by
Bot
The experimental probability of at least one coin landing on heads is the number of successful outcomes (HH, HT, TH) divided by the total number of trials. We can see from the table that out of 10 tosses, only 1 toss resulted in no head (TT), meaning the other 9 tosses had at least one head. Therefore, the experimental probability is 9/10 or 0.9.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.