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Sound intensity is inversely proportional to the square of the distance from the sound source; that is I= k/ (r)^(2), where I i...Asked by Michelle HELP PLEASE
Sound intensity is inversely proportional to the square of the distance from the sound source; that is
I= k/(r)^2,
where I is the intensity, r is the distance from the sound source, and k is a constant.
Suppose that I am sitting a distance R from the TV, where its sound intnesity is I(base 1). Now you move to a seat five times as far from the TV, a distance 5R away, where the sound intensity is I(base 2).
WHAT IS THE RELATIONSHIP BETWEEN I(base 1) AND I(base 2)?
I(base 2)=_____
I have tried I(base 2)= (1/5)(I-I(base 1) BUT IT IS WRONG
PLEASE HELP:(
I= k/(r)^2,
where I is the intensity, r is the distance from the sound source, and k is a constant.
Suppose that I am sitting a distance R from the TV, where its sound intnesity is I(base 1). Now you move to a seat five times as far from the TV, a distance 5R away, where the sound intensity is I(base 2).
WHAT IS THE RELATIONSHIP BETWEEN I(base 1) AND I(base 2)?
I(base 2)=_____
I have tried I(base 2)= (1/5)(I-I(base 1) BUT IT IS WRONG
PLEASE HELP:(
Answers
Answered by
plumpycat
Intensity 1
= k / r ²
Intensity 2
= k / (5r) ²
= k / 25r ²
= (1/25) k / r ²
= (1/25) Intensity 1
= k / r ²
Intensity 2
= k / (5r) ²
= k / 25r ²
= (1/25) k / r ²
= (1/25) Intensity 1
Answered by
Michelle HELP PLEASE
Thank you sooooo much!!!!!! @plumpycat
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