Asked by Helen
Sound intensity is inversely proportional to the square of the distance from the sound source; that is
I= k/ (r)^(2),
where I is the intensity, r is the distance from the sound source, and k is a constant.
Suppose that you are sitting a distance R from the TV, where its sound intensity is I (base 1). Now you move to a seat five times as far from the TV, a distance 5R away, where the sound intensity is I(base 2).
what is the relationship between I(base 1) & I (base 2)?
What is the relationship between the decibel levels associated with I(base 1) & I (base 2)
-Round the decibel level for I(base 2) to the nearest integer.
The decibel level for I(base 2) is about __?__dB lower than I (base 1)
I= k/ (r)^(2),
where I is the intensity, r is the distance from the sound source, and k is a constant.
Suppose that you are sitting a distance R from the TV, where its sound intensity is I (base 1). Now you move to a seat five times as far from the TV, a distance 5R away, where the sound intensity is I(base 2).
what is the relationship between I(base 1) & I (base 2)?
What is the relationship between the decibel levels associated with I(base 1) & I (base 2)
-Round the decibel level for I(base 2) to the nearest integer.
The decibel level for I(base 2) is about __?__dB lower than I (base 1)
Answers
Answered by
Steve
I = k/r^2
Now replace r with 5r, and you have
I' = k/(5r)^2 = k/25r^2 = (1/25)(k/r^2)
If r is replaced with nr, then I gets scaled down by a factor of 1/n^2
Now replace r with 5r, and you have
I' = k/(5r)^2 = k/25r^2 = (1/25)(k/r^2)
If r is replaced with nr, then I gets scaled down by a factor of 1/n^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.