1g mixture of Cu2O and CuO on heating gives 0.88g of copper. Calculate % of CuO in mixture

Answer 1

Two equations in two unknowns and you solve them simultaneously.

2CuO ==> 2Cu + O2
2Cu2O ==> 4Cu + O2
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Let x =g CuO
and y = g Cu2O
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eqn 1 is x + y = 1g

eqn 2. This converts Cu from CuO and Cu from Cu2O to grams Cu that you end up with of 0.88 g. mm stands fr molar mass. am stands for atomic mass.
x(2*am Cu/2*mm CuO) + y(4*am Cu/2*mm) = 0.88 Cu2O

Solve the two equations simultaneously for x and y. x gives you grams CuO.
Then %CuO = (g CuO/1 g)*100 = ?

Post your work if you have trouble.