Asked by Anonymous
                Yumi walked 2 km to a bus stop to catch the bust to school. The bus arrived straight away and averaged 60km/h for the 5km trip.
Yumi's total travelling time was 25 minutes.
at what average speed did Yumi walk to the bus stop?
The answer is 6, but the only thing I could think of to get to there is 60km/h / 5km trip
is 12mins for the bus trip, which leaves 13 minutes left, and dividing that by 2 km to get the km/h, which would equal 6.5.
            
        Yumi's total travelling time was 25 minutes.
at what average speed did Yumi walk to the bus stop?
The answer is 6, but the only thing I could think of to get to there is 60km/h / 5km trip
is 12mins for the bus trip, which leaves 13 minutes left, and dividing that by 2 km to get the km/h, which would equal 6.5.
Answers
                    Answered by
            Anonymous
            
    time on bus = (5/60)hr
= (5/60)(60) = 5 minutes
so he walked for 20 inutes
20 minutes (1 hour/60 min) = (1/3)hr
2 km/(1/3)hr = 6 km/hr
    
= (5/60)(60) = 5 minutes
so he walked for 20 inutes
20 minutes (1 hour/60 min) = (1/3)hr
2 km/(1/3)hr = 6 km/hr
                    Answered by
            Reiny
            
    time on bus = distance / rate
= 5km/60 km/h
= .08333 hrs = 5 minutes
(you had distance = rate/distance !)
that leaves 20 minutes or 1/3 hour for walking the 2 km
rate of walking = 2/(1/3) = 2(3/1)
= 6 km/h
    
= 5km/60 km/h
= .08333 hrs = 5 minutes
(you had distance = rate/distance !)
that leaves 20 minutes or 1/3 hour for walking the 2 km
rate of walking = 2/(1/3) = 2(3/1)
= 6 km/h
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.